QPermission 类

qApp->checkPermission(QCameraPermission{});
					

qApp->requestPermission(QCameraPermission{}, [](const QPermission &permission) {
    if (permission.status() == Qt::PermissionStatus:Granted)
        takePhoto();
});
					

QLocationPermission locationPermission;
locationPermission.setAccuracy(QLocationPermission::Precise);
qApp->requestPermission(locationPermission, this, &LocationWidget::permissionUpdated);
					

void LocationWidget::permissionUpdated(const QPermission &permission)
{
    if (permission.status() != Qt::PermissionStatus:Granted)
        return;
    auto locationPermission = permission.value<QLocationPermission>();
    if (!locationPermission || locationPermission->accuracy() != QLocationPermission::Precise)
        return;
    updatePreciseLocation();
}
					
					

类型化权限

下列权限是可用的：

另请参阅 应用程序权限 .

成员函数文档编制

template <typename T, QPermission::if_permission<T> = true> QPermission:: QPermission (const T & type )

构造权限从给定 类型化权限 type .

You do not need to construct this type explicitly, as the type is automatically used when checking or requesting permissions.

This constructor participates in overload resolution only if T is one of the 类型化权限 类：

Qt::PermissionStatus QPermission:: status () const

返回权限的状态。

QMetaType QPermission:: type () const

Returns the type of the permission.

template <typename T, QPermission::if_permission<T> = true> std::optional < T > QPermission:: value () const

返回 类型化权限 类型 T ，或 std::nullopt 若此 QPermission object doesn't contain one.

使用 type () for dynamically choosing which typed permission to request.

此函数仅参与重载解析，若 T is one of the 类型化权限 类：